Appendix 1- Materials

1.
Isovent chart (*P8
Source 1*)

2.
NEG Micon Technical Specifications Example One (*Source 5*)

3.
A refuse-burning power station (Page 30 *Source 16*)

Appendix 2- Correspondence

1)

To whom it may concern:

I am currently doing an investigation
for A-Level Physics, and need to know the sources of all my materials. Could
you please tell me the name(s) and position(s) of the author(s) (if there is a
few, otherwise the name of the group) of "**NEW AND RENEWABLE ENERGY
Prospects for the 21st Century**", and it's **Supporting
Analysis**, both** **found at http://www.dti.gov.uk/renew/condoc/.

I have to hand it in fairly soon so a
speedy reply would be much appreciated. Many thanks.

Simon … (UK Student)

Details:

Address:

The Lodge

Botton Village

Danby

Whitby

North Yorkshire

YO21 2NJ

England

Email Address:

Telephone:

0044 (0)1287 661 201

Simon

The consultation paper was written (in consultation with other Government
Departments) and published by the DTI on 30 March 1999. The supporting analysis
was prepared and published, at the same time, by the Energy Technology Support
Unit for the DTI.

Neil Hornsby

2)

Simon …

Address

Email:
advanced_levels@hotmail.com

Nedwind
b.V.

Remmerden
9

Rhenen

P.O.
Box 118

3910
AC Rhenen

To
Whom It May Concern:

I
am an A-Level Physics student and am currently investigating the potential of
wind as an energy resource for the United Kingdom in the future. I would be
very grateful for any information on wind energy, particularly physical,
mechanical and statistical.

Many
thanks,

Yours Faithfully

Simon …

Dear Mr. …,

With reference to your letter dated June 7,1999 we inform you as follows.

Since October 1, 1998 we are a subsidiary of NEG Micon.

As they are responsible for the UK market we kindly request you to contact them
directly.

Please find below the address:

NEG Micon UK Ltd.

Taywood House, 345 Ruislip Road

SOUTHALL, UBI 2Q X

United Kingdom

tel; 0044 -1932732500

We trust to have been of service to you with this information,`

With kind regards,

Christine van Leeuwen

Secretary Marketing & Sales

__ __

Simon …

Address

Email:
advanced_levels@hotmail.com

NEG
Micon UK Ltd.

Taywood House, 345 Ruislip Road

SOUTHALL, UBI 2Q X

United Kingdom

To Whom It May Concern:

I
am an A-Level Physics student at Stokesley Sixth Form College

I
am currently investigating the potential of wind as an energy resource for the
United Kingdom in the future. I am interested in any information on wind
energy, particularly physical, technical and statistical.

If
you could be of assistance to me, I would be extremely grateful.

Yours
Faithfully

Simon

Appendix 3- Derivations

(Derivation of Betz’s Law)

Consider a single stream of particles. The mass of particles m passing through a certain point at each moment in time will be given by:

m
= __v M__

d

Where d =
distance between particles, M = mass of each particle and v = velocity of
particles.

If we consider
the mass of particles flowing through a certain area, like that, which the
rotor blades sweep through (as shown above), an area term would have to be
added and distance would turn into volume per particle. The equation would
become

m
= __v A M__

V

Where A = area through which the blades sweep and V = volume taken up by each particle, with A being perpendicular to the direction of v. Since the density of air, r, is given by

r = M/V

, the mass of the air passing through the area of the turbine blade shown above can therefore be calculated by

m
= r A v

where m= mass
per second, r = air density (Kg/m^{3}),
A = the area swept through by the rotor and V = velocity of the wind through
the turbines. The latter we will assume to be the average wind speed, (V_{1}+V_{2})/2
(see above diagram), which makes the equation for any length of time t

m
= r A t (v_{1} + v_{2})/2

Power is given by

Power
= __energy transferred__

time taken

Energy is given by

Energy
transferred = ½ m v^{2}

Therefore

Power
= __m ____D____ v ^{2}__ =

2 t 2 t

Rearrange and substitute this into the original equation

(m = r A
t (v_{1} + v_{2})/2) to get

__ 2 P t
__ = __r __ A t (v_{1} + v_{2})

(v_{1}
– v_{2})^{2} 2^{}

If we go through
the same process to find the total power in the undisturbed wind flowing
through the same area A, we get the value P_{0} as

We can then calculate the ratio of
P to P_{0} (the power we extract to the power in the undisturbed wind):

·
Using the equation derived by Betz (*Appendix 3*), we can plot P/P_{0}
as a function of v_{2}/v_{1}, as shown below. We can see that
the function reaches its maximum for v_{2}/v_{1} = 1/3, and
that the maximum value for the power extracted from the wind is 0,59 or 16/27
of the total power in the wind.